find the domain of the function F(X) =√x² +3x-28

Answer 1

f(x) = sqr(x^2 +3x -28)

f(x) = sqr((x+7)(x-4))

x^2 + 3x -28 has to be equal to or greater than zero

there's 3 intervals x<-7, -7<x<4, and x>4

the domain is any real number except -7<x<4, as that gives an imaginary value for f(x)

domain is (-inf, -7) U (4, inf)