Can someone please help and check-over my answers to these Chemistry problems?

Question

 _______ will have a higher entropy than 50.0 g CO₂ (g) at 56 ^oC.

A. 25.0 g CO2 (g) at 56 oC

B. 50.0 g CO2 (g) at 50 oC

C. 50.0 g CO2 (l) at 56 oC

D. 55.0 g CO2 (l) at 56 oC

E. 55.0 g CO2 (g) at 56 oC

 

In which of the following equations is ΔS negative? _______

A. 4NH3 (g) + 5O2 (g) → 4NO (g) + 6H2O (g)

B. Zn (s) + HCl (aq) → ZnCl2 (aq) + H2 (g)

C. NaCl (s) + H2SO4 (l) → NaHSO4 (s) + HCl (g)

D. 2NH4NO3 (s) + Ba(OH)2(H2O)8 (s) → Ba(NO3)2 (aq) + 2NH4OH (aq) + 8H2O (l)

E. NaCl (aq) + H2O (l) + CO2 (g) → NaHCO3 (aq) + HCl (l)

 

What is the ΔH^o of the equation 2C₆H₆ (l) + 15O₂ (g) → 12CO₂ (g) + 6H₂O (g)? Given: ΔH_f^o C₆H₆ = 49.00 kJ/mol, ΔH_f^o CO₂ = –394 kJ/mol, ΔH_f^o H₂O = –242 kJ/mol.

A. ΔHo = –6,082 kJ

B. ΔHo = –6,278 kJ

C. ΔHfo = 6,082 kJ

D. ΔHfo = 6,278 kJ

E. None of the Above

The symbol _______ stands for the energy required to break bonds minus the energy released when bonds are broken.

A. ΔE

B. ΔG

C. ΔH

D. ΔS

E. ΔT

 

 

Answer 1

1) Higher entropy for more stuff and higher temperature gas. Check

2) Higher entropy going from s --> liquid --> liquid solution --> gas

Higher entropy with mixing

Higher entropy with decomposition

Higher entropy with more moles.

Dominant is 1st statement. Your choice is the only one that makes sense for negative entropy. (lost a gas and fewer moles)

3) Check

4) The enthalpy change is equal to bond energy broken in reactants energy - bond energy formed in products. (all bond energies considered +) Only one incorrect.

Please consider a tutor. Take care.