Michael J. answered • 03/10/15

Tutor

5
(5)
Best Afterschool Tutor to Prepare You For Your Regents

log1632 = x + 2

The solution to a logarithm is the exponent. The base number of a log is 10.

10

^{(}^{x}^{ + 2}^{)}= 1632Log both sides of the equation and bring the exponent down as the coefficient of the log.

(x + 2)log10 = log(1632)

Divide both sides of equation by log10.

x + 2 = 3.21

Subtract 2 on both sides of equation.

x = 1.21