Pb2+ + Cl2-1 -----> PbCl2
Pb = 1 x 207.2 = 207.2
Cl = 2 x 35.5 = 71
18g PbCl2 x 1 mol PbCl2/278.2 g PbCl2 x 1 mol Cl2/1 mol PbCl2 x 71 g Cl2/1 mol Cl2 = 4.59 g Cl2
Tran A.
asked 10/13/21Pb2+ + Cl2-1 -----> PbCl2
Pb = 1 x 207.2 = 207.2
Cl = 2 x 35.5 = 71
18g PbCl2 x 1 mol PbCl2/278.2 g PbCl2 x 1 mol Cl2/1 mol PbCl2 x 71 g Cl2/1 mol Cl2 = 4.59 g Cl2
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