What is the mass in grams of 4.86 x 1023 atoms of vanadium (V)?

Answer 1

Hello, Tran,

I just answered a similar problem you posted for sugar. Please follow the guideline there for Vanadium, V, element 23, atomic mass 50.942.

1 mole of V has a mass of 50.942 g. Therefore, it's molar mass is 50.942g/mole. There are 6.022x10²³ molecules/mole of anything. If you have 4.85x10²³ atoms, you can find the number of moles by dividing by Avogadro's number:

(4.85x10²³ atoms)/(6.022x10²³ atoms/mole) = 0.807 moles of V. Convert that to grams by multiplying by the atiomic mass of V, 50.928 g/mole:

(0.807 moles of V)*(50.928 g/mole) = 41.1 grams of V

Bob

Answer 2

Hello Tran,

I'm not going to give you the answer to this specific question, but I will provide you with an example that is similar.

Question: What is the mass (jn grams) of 1.34 x 10²⁵ atoms of carbon?

Answer: (1.34 x 10²⁵ atoms C) * (1 mol C / 6.022 x 10²³ atoms C) * (12.011 g C / 1 mol C) = 267 g C

In order to solve these types of problems, you must use Avogadro's constant (6.022 x 10²³ mol^-1) and the molar mass (g/mol) of the specific element. I hope this helps.

Sincerely,

Michael