Calculate the molarity of 30.1 g of MgS in 913 mL of solution. molarity: M

Answer 1

Molarity is moles/liter.

913 mL = 0.913 L

To determine the number of moles in 30.1 g of MgS, look up both Mg and S on the periodic table:

Mg = 24.305 g/mole

S = 32.066 g/mole

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MgS = 56.371 g/mole

So 30.1 g is 30.1/56.371 = 0.53396 moles

So the molarity is (0.53396 moles)/(0.913 L) = 0.585 moles/liter or 0.585 M