Find the slope of the tangent line to the parabola y=x^2−3x−1 at the point (5,9).

Question

please help i don't know how to do this

Answer 1

One thing you should always remember that the derivative of a function is the slope of the tangent line.

So if the given is:

y=x²-3x-1,

the slope of the tangent line is:

y' = 2x-3

The given point is (5,9). It means x=5

y'=2(5)-3

y' = 7