
Anthony T. answered 10/07/21
Patient Science Tutor
The amount of titrant gives you the number of moles of HB present in the solution as HB + HBr ==> H2B1+ + Br1
0.753 moles / L or 0.753 moles / 1000 mL x 32.60 ml HBr = 0.0245 moles HBr = 0.0245 moles HB.
The molarity of the final titrated solution is 0.0245 / (32.0 + 32.6 mL)x 1000 = 0.379 M.
As this solution undergoes hydrolysis, we can calculate the pH of the final solution using the Kb.
HB + HOH =====> H2B1+ OH1-.
Kb = [OH1-]2 / [HB] = [OH1-]2 / 0.379 = 1.7 x 10-9. Use the approximation that [HB] = 0.379 M.
[OH-] = √ (1.7 x 10-9 x 0.379) = 2.54 x 10-5 or pOH = 4.60, pH = 14 - 4.60 = 9.4
You would select an indicator that changes color around that pH. phenolphthalein will work.
As we determined that 0.0245 moles of HB are present and there is 1.94 g of HB, the molecular mass is
1.94 g / 0.0245 moles =79.2 g/mole