We can use h=1/2 * g * t2
we know h = 121 and g =2
t = sqrt (2h/g)
t = sqrt( 242/2) = 11 seconds
David C.
asked 10/06/21in the moon gravitional acceleration is about 2m/s^2. How many seconds does it take for an object to fall from a height of 121
We can use h=1/2 * g * t2
we know h = 121 and g =2
t = sqrt (2h/g)
t = sqrt( 242/2) = 11 seconds
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