For the dropped ball, the time is given by 20=.5gt^2 which gives t = 2.02 s
The velocity is given by v=0-gt and since we know t from before we get v = - 19.8 m/s
For the ball thrown down we need to set up a quadratic using y0 and y
0=20-4t-4.905t^2
4.905T^2+4t-20=0
t=1.65 s
The velocity is now given by v = -4 - 9.81 * 1.65 = -20.2 m/s
Amir H.
Thank you so much, wish you the best in life.10/04/21