
Sidney P. answered 10/04/21
Minored in physics in college, 2 years of recent teaching experience
Gravitational force Fg = GMm/r2 where M is mass of Earth in this case (5.98 x 1024 kg), m is mass of the satellite, and r is distance from Earth's center to the satellite. So r = RE + 2RE = 3 (6.40 x 103 km) = 19.2 x 106 m, and Fg = (6.673 x 10-11) (5.98 x 1024) (1.25 x 103) / (1.92 x 107)2 = 1,350 N.
For comparison, the weight of the satellite back on Earth was mg = 12,300 N, 9 times greater because it was 3 times closer to Earth's center.