The height of a triangle is 2 m more than twice the length of the base. The area of the triangle is 20m^2. Find the height of the triangle and the lenght of the base

Answer 1

h = 2+2b

A=hb/2 = (2+2b)b/2 = (1+b)b = b + b^2 = 20

b^2 + b -20 = 0

(b+5)(b-4) = 0

b -4 =0

b = 4 meters = base length

h=2+2b = 2+2(4) = 2+8 = 10 meters high