The area of a triangle is 119 cm². if the height of the triangle is 3cm less that its base, what is the measurement of its base and height?

Answer 1

h=b-3

A=hb/2 = (b-3)b/2 = 119

b^2 -3b = 119(2) = 238

b^2 -3b -238 = 0

(b-17)(b+14) =0

b -17 =0

b = 17 meters = base length

h=17-3 = 14 meters high