Calculating Mass of Solid (Titration Problem)

Question

Calculate the mass of NaOH_(s) that must be dissolved in exactly 1L of solution so that 29.00 mL of this solution is required to titrate to the equivalence point a solution containing 0.2747 g of a monoprotic acid with a molar mass of 119.3 g/mol.

Molar mass of NaOH = 39.997 g/mol

Give your answer in grams (g) with the correct significant digits.

Answer 1

H^+ + OH^- => H2O

#mol H^+ = #mol OH^-

#mol H^+ = 0.2747g / (119.3g/mol) = 2.303×10^-3 mol

#mol OH^- = #mol NaOH = 2.303×10^-3 mol

Mass of NaOH = 2.303×10^-3 × (39.997 g/mol) = 0.09210 g