If the pH of an aqueous solution at 25.0 °C is 10.10, what is the molarity of H+ in this solution?

Question

A. 3.90

B. 7.9*10^-11

C. 1.3*10^10

D. 1.0*10^-13

E. 1.3*10^-4

Answer 1

pH=-log[H+] , pH is given. The concentration units are moles/liter which is equal to molarity.

10.10= -log[H+]

to get rid of negative in front of log, multiply both side with (-)

-(10.10)= -(-log)[H+]

take the antilog from both side to get the molarity. Note--> taking the antilog cancel the log in front of the molarity.

10^-10.10 =[H+]

= 7.9*10^-11

the correct answer is B