a ball rolling at 4.0 m/s accelerates uniformly down a hill at 5.5 m/s^2 for 6.0 sec. What is the final velocity?

Answer 1

Solution:

Using the equation of motion:

V_f = V_o + at = 4.0 m/s + (5.5m/s²)(6 s) = 4.0 m/s + 33 m/s = 37 m/s