a car traveling 6.0 m/s is uniformly accelerating at a rate of 3.0 m/s^2 for 15 sec. What is the final velocity?

Answer 1

Solution:

the general distance formula is X = 1/2at² + V₀t + X₀ . With the car not starting from rest X₀ ≠ 0

Taking the derivative of X wrt to time, dX/dt = at + V₀ = V_f , then V_f = (3.0 m/s²)(15s)+6.0m/s

V_f = 45m/s + 6 m/s = 51 m/s