What is the resultant force on the box if it is pushed up with 100 N of force?

Question

1. A 12 kg box is being pushed up a ramp of 30 ^o. The frictional force is k=0.15. What is the resultant force on the box if it is pushed up with 100 N of force? 
2. cos(30 ^o) = 0.866
3. sin(30 ^o) = 0.5

	A.	41.2 N
	B.	84.7 N
	C.	-10.66 N
	D.	25.92 N

Answer 1

F_net=F_θapplied - mgsin(θ) -kmgcos(θ)=(100 N) -(12 kg)(9.8/ m/s²)sin(30⁰) -0.15(12 kg)(9.8/ m/s²)cos(30⁰)=25.92 N\

Where mgsin(θ) gravitational force component along the incline

kmgcos(θ) friction force