How fast is the car going after 6 seconds of traveling up the hill?

Question

1. A car is at the bottom of a hill with an incline of 20^o, and it starts to accelerate up the hill by pressing on the gas. It started at 15 m/s, and it has a mass of 1200 kg, and accelerates his car at 3 m/s². Assume negligible friction (k = 0), how fast is the car going after 6 seconds of traveling up the hill? 
2. cos(20^o) = 0.9397
3. sin(20^o) = 0.3420

	A.	12.89 m/s
	B.	17.1 m/s
	C.	-2.1 m/s
	D.	-22.254 m/s

Answer 1

a_net= a_car -gsin(20⁰)=-0.3518 m/s² (3.0-9.8*0.342)

Then V(t)= V(0)- a_nett=3 m/s -(0.3518 m/s²)*(6s)=12.89 m/s

gsin(20⁰) is component of free fallen acceleration along the incline