Let's list forces exerted on the box along the incline: Fapplied - mgsinθ -kmgcosθ=Fnet
where Ffriction=kmgcosθ and mgsinθ is gravitational force component along the incline.
Hence Fnet=(400 N) -(60 kg)(9.8 m/s2)sin (300) -0.07(60 kg)(9.8 m/s2)cos (300)=70.36 N