0/2 An egg is dropped from rest. How long will it take for the egg to hit the floor 1.2 meters below its release point?

Answer 1

Solution:

The equation for free falling bodies is y = -1/2 gt² + v₀t + y₀ here y = 0, and y₀ = 1.2m

Also v_o = 0 initial velocity at rest. Substituting all of that 0 = -1/2 gt² + 0 + 1.2 , 1.2 = 1/2 gt² , 2.4 = gt² and

t² = 2.4 /g = 2.4 m / 9.81 m/s² = 0.244 s² , and t = √0.224 s² = 0.494 approximately 0.5 s. Note that the mass of the egg does not affect the time of the free fall.