Help with do while loop

Question

generate a random number between 5 and 250. This will be the number of values in the third set. Display a label such as "3rd set of random numbers" and the number of values in the set.

Using a do while loop that executes exactly "number of values in the third set" number of times:

1. generate a random number between 1 and 100
2. display the random number

When displaying the random numbers, make sure that there are exactly 8 values displayed per line. The exception is the last line, which may have less than 8 values displayed.

this is all I have and I'm stuck.

i = 0;

const double MAXIUMUM3 = 250;

cout << "Third set of numbers" << endl;

RandNum = rand() % 250 + 5;

cout << "There are " << RandNum << " numbers in the set" << endl << endl;

do {

RandNum = rand() % 100 + 1;

cout << RandNum << ' ';

++i;

} while (i < MAXIMUM3);

Answer 1

Hi James, hope this helps!

#include <iostream>

#include <stdlib.h>

#include <time.h>

int main() {

// Seed rng

std::srand(time(NULL));

// Random number from 5 - 250

const int THIRD_SET = std::rand() % 245 + 5;

std::cout << "There are " << THIRD_SET << " numbers in the set\n\n";

int i = 0;

int valuesInLine = 0;

do {

std::cout << std::rand() % 100 + 1 << " ";

// Newline if there are 8 values in the line

if (++valuesInLine >= 8) {

std::cout << "\n";

valuesInLine = 0;

}

} while (++i < THIRD_SET);

return 0;

}