XeF4 → Xe + 2F2
Xenon tetrafluoride = XeF4
molar mass = Xe = 1 x 131.3 = 131.3
F = 4 x 19 = + 76
207.3 g/mol
5.697 g XeF4 x 1mol XeF4 x 1 mol Xe x 131.3 g Xe = 3.61 g Xe
207.3 g XeF4 1 mole XeF4 1 mol Xe
Andrea B.
asked 09/21/21Calculate the number of grams of xenon in 5.697g of the compound xenon tetrafluoride.
XeF4 → Xe + 2F2
Xenon tetrafluoride = XeF4
molar mass = Xe = 1 x 131.3 = 131.3
F = 4 x 19 = + 76
207.3 g/mol
5.697 g XeF4 x 1mol XeF4 x 1 mol Xe x 131.3 g Xe = 3.61 g Xe
207.3 g XeF4 1 mole XeF4 1 mol Xe
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