
Anthony T. answered 09/19/21
Patient Science Tutor
The efficiency of a Carnot engine is given by (Thot - Tcold ) / Thot . This is equal to the ratio of the maximum work obtainable from the heat transferred from the hot reservoir.
(Thot - Tcold ) / Thot = Wmax / Q where Q is the heat obtained from the combustion of 1.00 mole if CO. From the internet, I found a value of 283 kj / mole for the combustion if one mole of CO = Q.
Wmax = (723 - 273) / 723 x 283 kj = 176.1 kj.
The height to which a one kg mass can be lifted is h = Wmax / 1.00 kg x 9.8 m/s2.
h = 176.1 x 103 j / 1.00 kg x 9.8m/s2 = 17969 m. approximately as I used g to two sig figs.
Please check all calculations.