How many moles of methane CH4 are needed to produce 4.18 mol of water vapor H2O

Answer 1

Hello, Fadwa,

We need to start with a balanced equation for the combustion of methane. I come up with:

CH₄ + 2O₂ → CO₂ + 2H₂O

This tells us that 1 mole of methane will produce 2 moles of H2O. We can write:

(1 mole CH₄)/(2 moles H₂O)

If we want 4.18 moles of water vapor. we can multiply this times the molar ratio, above:

(4.18 moles H₂O)*(1 mole CH₄)/(2 moles H₂O) = 2.09 moles CH₄

2.09 moles CH₄ will produce 4.18 moles of H₂O

Bob