Consider the following reaction: 2 A (aq) + B (aq) ⇌ C (aq) + D (aq) what is the equilibrium concentration (in M) of D?

Question

Consider the following reaction:

2 A (aq) + B (aq) ⇌  C (aq) + D (aq)

If the Kc for this equilibrium reaction is 44.9, and the equilibrium concentrations of A, B, and C are: [A] = 0.772 M, [B] = 0.0339 M, and [C] = 2.15 M, what is the equilibrium concentration (in M) of D?

Answer 1

K_c=[C][D]/[A]²[B]

44.9 = [2.15][D]/[0.772]²[0.0339]

[D] = 44.9*[0.772]²[0.0339]/[2.15]