The volume of gas in a container was originally 3.24L, while at standard pressure, 1.00atm. What will the volume be if the pressure is increased to 1.20atm?

Answer 1

For this you can use Boyle's Law (P1)(V1) = (P2)(V2) which comes from the ideal gas law (P1)(V1)/(T1) = (P2)(V2)/(T2). Since initial volume V1 = 3.24, initial pressure P1 = 1.00, and new pressure P2 = 1.20, substitute into Boyle's Law for (1.00)(3.24) = (1.2)(V2) and solve for V2. You should get 2.7L for the new volume.