Stoichiometry of Reactions: Gram to Gram

Question

According to the following reaction, how many grams of ammonium chloride are needed to form 28.8 grams of hydrochloric acid ?

ammonium chloride(aq)  ammonia(g) + hydrochloric acid(aq)

Answer 1

balance first:

NH₄Cl --> NH₃ + HCl (balanced)

convert to moles because the balanced equation is ALWAYS in moles. Then use the mole to mole ratio of NH₄Cl to HCl, Lastsly convert to grams of Ammonium chloride:

28.8g HCL * 1mol HCL / 36.45 g * 1 mol HCl / 1 mol NH₄Cl * 53.45g NH₄Cl / 1 mol =

Answer : 42.23 g Ammonium Chloride