Given .72 mole of oxygen gas how many mole of water can form

Question

2H-C=CH (g) + 5 O2(g) —> 4 CO2 (g) + 2H2O

Given 0.72 mole of oxygen gas how many mole of water can form?

Answer 1

Hello, Iris,

The balanced equation

2H-C=CH (g) + 5 O₂(g) —> 4 CO₂ (g) + 2H₂O

tells us that we will form 2 moles of water for every 5 moles of O₂. This gicves us a 2/5 molar ratio of water to O_2:

(2 moles H₂O)/(5 moles O₂)

If we start with 0.72 moles of O₂, we'll obtain:

(0.72 moles of O₂)*((2 moles H₂O)/(5 moles O₂)) = 0.288 moles H₂O. Round to 0.29 moles H₂O for 2 sig figs.

Bob