To find the probability of "at least one" it is often easier to do 1 - the complement,
so, 1 - P(neither become inoperative) = 1 - (2/3 * 5/6) = 1 - 5/9 = 4/9
Sarah B.
asked 09/14/21Suppose that two machines 1 and 2 in a factory are operated independently of each other. Let AA be the event that machine 1 will become inoperative during a given 8-hour period; let BB be the event that machine 2 will become inoperative during the same period; and suppose that P(A)=1/3 and P(B)=1/6. What is the probability that at least one of the machines will become inoperative during the given period? Answer exactly.
To find the probability of "at least one" it is often easier to do 1 - the complement,
so, 1 - P(neither become inoperative) = 1 - (2/3 * 5/6) = 1 - 5/9 = 4/9
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