49 total marbles 13 red
Event A = getting red on first draw
Event B = getting red on 2nd draw
P(A) = 13/49
P(B given A) = P(B|A) = 12/48 (since one less red marble and one less marble overall)
P(A and B) = P(A) * P(B|A) = 13/49 * 12/48 = 0.0663
Sarah B.
asked 09/08/21Suppose a jar contains 13 red marbles and 36 blue marbles. If 2 marbles are randomly chosen from the jar at the same time, find the probability that both marbles are red. Round your answer to four decimal places.
49 total marbles 13 red
Event A = getting red on first draw
Event B = getting red on 2nd draw
P(A) = 13/49
P(B given A) = P(B|A) = 12/48 (since one less red marble and one less marble overall)
P(A and B) = P(A) * P(B|A) = 13/49 * 12/48 = 0.0663
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