Roger N. answered 09/08/21
. BE in Civil Engineering . Senior Structural/Civil Engineer
Solution:
The general Newton 2nd Law is ∑F = ma , the forces present are Drive force due west FD = +3510 N, wind force due east Fwind = -640N , and water force due east Fw = -1710 N.
∑F = ma, FD+ Fwind + Fw = ma , +3510 N -640 N -1710 N = 4040 kg (a) , 1160 N = 4040 kg ( a) and
a = 1160 N / 4040 kg = 1160 kg.m/s2 / 4040 kg = 0.287 m/s2