If we react 2,37g of diborane, how many grams of water would we expect to produce

Answer 1

A plausible diborane reaction producing water is : 2 B₂H₆ + 6 O₂ --> 2 B₂O₃ + 6 H₂O.

Stoichiometry: (2.37g diborane) * (1 mole diborane / 27.66g diborane) * (6 mole H₂O / 2 mole diborane) * (18.02g H₂O / 1 mole H₂O) = 4.63g water.