
Elva V.
asked 09/04/21One difference between first- and second-order reactions is that ________.
A. the rate of both first-order and second-order reactions do not depend on reactant concentrations
B. the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
C. a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
D. the rate of a first-order reaction depends on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
E. None of the above are true.
1 Expert Answer
Lydia F. answered 09/04/21
Doctor of Pharmacy Specializing in Chemistry (10+ years experience)
Hi Elva!
The correct answer is B. Let's go through all of the answer choices to see why:
A. the rate of both first-order and second-order reactions do not depend on reactant concentrations
The rate law for a first-order reaction is Rate = k[A] and the rate law for a second-order reaction is
Rate = k[A]2, where [A] is the concentration of reactant A. As we can see, the concentration of A is in both rate laws. This means that the rates of both types of reactions DO depend on reactant concentrations. The rate of zero-order reactions, in contrast, does not depend on reactant concentrations.
Please note, a rate law for a second-order reaction that depends on the concentration of two reactants is
Rate = k[A][B], where [A] is the concentration of reactant A and [B] is the concentration for reactant B. As you can see, the rate for this type of second-order reaction is also dependent on the concentration of the reactants. This answer is incorrect.
*B. the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0 - Correct Answer!
Let's look at the equations for half-life (t1/2) for each type of reaction.
First-order:
t1/2 = 0.693/k
(you might also see this as ln(2)/k, which is the same thing)
Second-order:
t1/2 = 1/k[A]0, where [A]0 is the initial concentration of reactant A.
Notice how the concentration of A is NOT in the equation for the half-life of a first-order reaction, but the concentration of A IS in the equation for the half-life of a second-order reaction. This means that the half-life of a first-order reaction does not depend on initial concentration ([A]0), but the half-life of a second-order reaction does depend on initial concentration. This answer is correct.
Please note that the half-life of a zero-order reaction also depends on the initial concentration, [A]0.
C. a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
A catalyst is a substance that increases the rate of reaction without itself being consumed. It does so by providing an alternative, lower-energy pathway (thereby decreasing the activation energy). Second-order reactions can be catalyzed. This answer is incorrect.
D. the rate of a first-order reaction depends on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
As we saw in answer choice A, when looking at the rate laws of first-order and second-order reactions, the rates of both types of reactions do depend on reactant concentrations. Zero-order reactions do not depend on reactant concentrations. This answer is incorrect.
E. None of the above are true.
Answer choice B is true, so this answer is incorrect.
I hope this helps! Please comment if you have any additional questions! :)
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Ofure A.
A second order reaction does not depend on the concentration. So the answer for this is D.09/04/21