
Leo Chun Hung L. answered 08/25/21
Experienced Tutor in Physics and Mathematics
(a)
2,000 A + 3,000 B >= 120,000;
A + B <= 50;
B <= 2A
A >= 0
B >= 0
(b) Profit(A,B) = 10,000 A + 20,000 B
Graphing (a), the feasible solutions are in a shape of triangle. Construct a straight line L: 10,000 A + 20,000 B = 0. Construct L' such that it is parallel to L and move towards the top right corner (which are larger A and B for larger profit). The max profit is located at the intersection of B = 2A and A + B = 50. By solving the simultaneous equations, A = 50/3, B = 100/3. According to B <= 2A, B cannot be more when rounding. So we round down B to 33 and A will be 17. Finally, the max profit is 10,000 (17) + 20,000 (33) = Ksh 830,000.
(c) The transporter should retain Truck type B since it contains more and earns more for each trip.