
Anthony T. answered 08/23/21
Patient Science Tutor
Cp = 0.90 j/g C
Mass = 420 g
ΔT = (232 - 22) C = 210C
Q = 0.90 j/g C x 420 g x 210 C = 79380 j
Karanbir S.
asked 08/23/21How many joules of heat must be transferred to a 420-g aluminum pizza pan to raise its temperature from 22°C to 232°C? The specific heat of aluminum in this temperature range is 0.90 J/g·°C. Show your work. Q = (mass) (Cp) (ΔT)
Q =
Cp =
Mass =
ΔT =
Anthony T. answered 08/23/21
Patient Science Tutor
Cp = 0.90 j/g C
Mass = 420 g
ΔT = (232 - 22) C = 210C
Q = 0.90 j/g C x 420 g x 210 C = 79380 j
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