Find an equation of the Line L that contains the points (0,0) and (5,3).

Answer 1

1. Slope (m) = (y₂ - y₁) / (x₂ - x₁)
2. x₁=0, y₁=0, x₂=5, y₂=3
3. Slope (m) = (3 - 0) / (5- 0) = 3/5
4. 3/5 = (y - 0)/(x - 0)
5. 3/5 = y/x
6. y = 3x/5 The equation of the line

Answer 2

Let the points be ( 0,0) for ( x1,y1) and (5,3) for (x2,y2)

To find the equation of the line you need to find the slope m = (y2-y1)/(x2-x1) = 3-0/ 5-0 = 3/5

The equation of the line has the slope of 3/5 and passes through the two points above. all you nee to write the equation is one point lets choose ( 5,3) . In slope form m = 3/5 = ( y-3) / (x-5), cross multiply

y-3 = 3/5( x-5), y-3 = 3/5x -3 , and y = 3/5 x -3 +3 , y = 3/5x

if you have taken the first point ( 0,0) you would get the same answer. Try it