1) find the average rate in a time interval by taking the change in C divided by the change in t. The avg rate over first 20 seconds is (.54 - 0)mol of O2/liter/(20-0)sec = .027 mol/l-s.
2) Do the same for ozone reacting using concentrations of ozone: (1.64-2)/(20-0) = -.018 mol/l-s
The difference is due to the stoichiometry. You would expect rO2 = 3/2 rO3 with a change in sign because one is a reactant and the other a product.
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