Tamia L.

asked • 07/23/21

Please help me.

In the diagram, q1 = -4.60 x 10^-6 C, 92 +3.75 x 10^-6 C, and q3 = +8.30 x 10^-5 C. Find the direction of the net force on 93.

The diagram is a right triangle. Q1 is connected to Q3 (up-down) with a distance of 0.200 m. Q3 is connected to Q2 (right-left) with a distance of 0.200 m. Q2 is connected to Q1 (diagonally) with a distance of 0.283 m. Q2 has an interior angle of 45 degrees.


1 Expert Answer

By:

Tamia L.

I’m sorry Sir but I watched that entire video and it was wrong. I have been on this for days and I still can’t get past it.
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07/23/21

Roger N.

tutor
I found out what was wrong. It was the sign convention. One of the forces had the wrong direction. I am going to redo this problem and find the forces on charges q2 and q3. I am going to use the absolute value of the forces this time to avoid mistakes in force direction.
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07/24/21

Roger N.

tutor
I made another video but I couldn't post it. Can you repost the question so I can provide the video answer. In the mean time I am going to give you the answers . The force on q2 is 5.79 N at 166.3 degree rotating from the +ve x axis, and the force on q3 is 11.1 N rotating at 50.8 degree from the +ve x axis. If these are the correct solutions or approximately correct let me know so i can provide a video and explain how I got the answers.
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07/24/21

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