The molar mass of C12H22O11 is 342.1 g/mole.
Therefore: (0.0278 moles)*(42.1 g/mole) = 9.51 grams C12H22O11.
Cereal contains11.0 grams of sugar per 60.0 grams of cereal. We could write this as (11.0 grams sugar/60 g Cereal).
We can find the amount of cereal with the following: (11.0 grams sugar/60 g Cereal)*X = 9.51 grams sugar, where X is the grams cereal needed to obtain 9.51 grams sugar.
X = [(9.51
grams sugar)*(60 g cereal)]/(11.0 grams sugar)
X = 51.87 grams cereal will have 9.51 grams sugar.