Chemistry 122 j

Question

What volume of 0.40 M NaOH solution is needed to react completely with 28.0 mL of .55M HCl solution?

WET WET

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

Answer 1

Both the acid and the base are strong a acid/base meaning they will dissociate completely. this means we will need an equal number of moles of NaOH to neutralize the HCl in our 28.0 ml of .55M solution. Your math to find the amount of NaOH should follow this logic.

28 mL * (1L/1000mL) = 0.028L

0.028L * (0.55 Mol/1L) = 0.0154 mol

now we know our solution contains 0.0154 mol of HCl and we just need to solve for how much volume of NaOH is needed to get this many moles of NaOH

0.0154 mol NaOH * (1L/0.4mol) = 0.0385L

0.0385L * (1000mL/1L) = 38.5 ml of your NaOH solution.