Hello, Henry,
The equilibrium coefficient of water and its two ions, H+ and OH- is 1.0x10-14. This means that the product of the H+ and OH- concentrations equals 1.0x10-14.
In this case, [H+] = 8.1x10-3M
[OH-] = [1.0x10-14]/[8.1x10-3M]
[OH-] = [1.0x10-14]/[8.1x10-3M]
[OH-] = 1.2346x10-12
We can calculate pH, which is the negative log of [H+]
- log (8.1x10-3M)
pH = 2.09
pOH would be 14 - 2.09, or 11.81
Bob