Tom K. answered 07/18/21
Knowledgeable and Friendly Math and Statistics Tutor
a) For this problem, x-bar is the sample mean
P(x1,x2, ... ,xµn) = µe-µx1 * µe-µx2 * ... * µe-µxn = µne-µ∑xi = µne-nµ x-bar
b) It is easier to maximize the log likelihood = n ln µ - n µ x-bar
d ln(P)/dµ = n/µ - n x-bar
n/µ - n x-bar = 0
n/µ = n x-bar
n µ x-bar = n
µ = 1/x-bar