Raymond B. answered 07/11/21
Math, microeconomics or criminal justice
f(x) = y = 2(x-3)^2 +1
switch x and y and solve for the new y
x = 2(y-3)^2 + 1
(x-1)/2 = (y-3)^2
y - 3 = + or -sqr[(x-1)/2]
y = 3 + sqr[(x-1)/2] = an inverse relation, but not an inverse function
there is no inverse function, unless you ignore either the - or + square root.
It's then an inverse function of half of the original function.