What is the mass, in grams, of 9.35×1024 molecules of methanol (CH3OH)?

Question

What is the mass, in grams, of 9.35×1024 molecules of methanol (CH3OH)?

Answer 1

Remember 1 mole of any substance has Avogardo's number.of molecules. The problem follows direct proportion.

I mole of methanol (CH₃OH) has a mass of (12+4+16) = 32g and has 6.02× 10²³ molecules.

Thus 9.35 × 10²⁴ molecules of methanol have a mass of (32 × 9.35 × 10²⁴)/⁽6 × 10²³) in grams.

Answer 2

Mass(g)=(32.04g* 9.35*10²⁴ molecules)/(6.022*10²³ moleculaes)=497.47g