According to the following reaction, how many grams of barium sulfate will be formed upon the complete reaction of 21.4 grams of sulfuric acid with excess barium hydroxide?

Question

barium hydroxide (aq) + sulfuric acid (aq) barium sulfate (s) + water (l)

Answer 1

First, balance the reaction:

Ba(OH)₂ + H₂SO₄ → BaSO₄ + 2 H₂O

(217.4 g BaSO₄/1 mol BaSO₄) (1 mol BaSO₄/1 mol H₂SO₄) (1 mol H₂SO₄/98.1 g H₂SO₄) 21.4 g H₂SO₄

= 47.4 g BaSO₄