If 2.25 mol of an ideal gas has a pressure of 6.90 atm and a volume of 16.33 L, what is the temperature of the sample?

Answer 1

To solve for Temperature we use the ideal gas law! (P*V=n*R*T)

We want to use the ideal gas constant that corresponds to the given units of Pressure and volume. (R= 0.08206 L*atm / (mol* K))

We need to rearrange the formula to solve for T. We divide both sides by n*R and what we are left with is:

T = P*V / (n*R). Using P = 6.90 atm, V = 16.33 L, and n = 2.25 mol, we get that temperature is 610.27 K.