red car is going about 81.86 ft/sec
let distance between the police and red cars = h
distance from the red car to a point horizontal to the police car = a
distance from from the road to the police car = b
h^2 = a^2 + b^2
take the derivative with respect to time
hh' = aa' + bb' b'=0
174.64(75) = 160a'
a' = 174.64(75)/160 = 81.86
81.86 ft/sec = 81.86(5280)/60^2 = about 120.06 mph
1 mile = 5280 feet
1 hour = 60 minutes x 60 seconds = 3600 seconds
1 mile per hour = 5280 feet per 3600 seconds
1 foot per second = 5280/3600 mph = 1.4666...mph
81.86 x 1.4666... = 120.061333...
an arrest for reckless driving, maybe felony endangerment is about to happen, with radar evidence enough to convince any jury, unless it wasn't calibrated properly or failed quality assurance tests. The prosecutor and police may hide any evidence that discredits that radar results though. Some jail time is likely, unless no prior driving problems or criminal record. if the red car driver doesn't believe he was going 120 mph, his attorney should make a motion for disclosure of everything about the radar and officer. There may be similar cases where he falsely arrested drivers for speeding based on faulty radar or his own need to fill a quota or tickets or arrests. Worse than jail or possible prison is the suspended maybe revoked drivers license plus huge fine and huge increase in insurance premiums if you can get any insurance.
Take a square with 4 sides each = s = 24 m
a circle inside with radius = 5
the area between the square and circle = s^2 - pir^2
take the derivative with respect to time
A' = 2ss' - 2pirr' = 2(24)(-4) - 2pi(5)(2) = -192 - about 62.8318 = about -129.1682 m^2/hour
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Thank you so much. Could you also help me with this problem? The radius of the circle is increasing at a rate of 2 meters per hour and the sides of the square are decreasing at a rate of 4 meters per hour. When the radius is 5 meters, and the sides are 24 meters, then how fast is the AREA outside the circle but inside the square changing? The rate of change of the area enclosed between the circle and the square is _____ square meters per hour.07/02/21