Determine all natural number divisible by 8 whose sum of digits is less than 10 and the product of digits is equal to 12.

Question

Determine all natural number divisible by 8 whose sum of digits is less than 10 and the product of digits is equal to 12.

Answer 1

12 =6x2 or 4x3 or 12x1

62, 26, 43, 34, 121 or 112

112/8 = 14 only 112 is divisible by 8

and

1+1+2 < 10

but you probably meant product of individual digits, then 1x1x2 doesn't = 12

so, 2 x 3 x 2 = 12

232/8 = 29

6x2x1 = 12

216/8 = 27

232 and 216 are two natural numbers divisible by 8 whose digits sum to less than 10

if the product is 12, one of the digits has to be even. there has to be a 2, 4 or 6 in the number at the end to be divisible by 8

314, 134 aren't divisible by 8