The distance between 2 3/4 and -1 5/6 on the real number line is

Question

The distance between 2 3/4 and -1 5/6 on the real number line is

Answer 1

Hi Noor,

You can use absolute value to help you solve this problem (absolute value is the distance a number is from zero on a number line).

First 2 3/4 is to the right of 0 and is located 2 3/4 spaces from zero.

Then -1 5/6 is located 1 5/6 spaces away from zero.

The distance between the two values would be the sum of their distances from zero or:

2 3/4 + 1 5/6 = 2 9/12 + 1 10/12 = 3 19/12

This mixed number can be written as 4 and 7/ 12.

This distance will be 4 7/12